问题描述:设随机变量(X,Y)的联合密度函数为f(x,y)={21/4x^2y,x^2最佳答案: fx(x)=∫x2~1 21/(4x2y) dy = (21/4x2)ln(y) |(y:x2~1) =(21/4x2)(-lnx2) fy|x(y|x)=f(x,y)/fx(x)=(1/y)/(-lnx2)=-1/(ylnx2)x=1/2时,密度函数=-1/(yln(1/4... 点击显示答案